11z/2z^2=2

Solution for 11z/2z^2=2 equation:

11z/2z^2=2

We move all terms to the left:

11z/2z^2-(2)=0


Domain of the equation: 2z^2!=0

z^2!=0/2

z^2!=√0

z!=0

z∈R


We multiply all the terms by the denominator


11z-2*2z^2=0

Wy multiply elements

-4z^2+11z=0

a = -4; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-4)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-4}=\frac{-22}{-8}
=2+3/4
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-4}=\frac{0}{-8}
=0
$